2(1/3k-6)^2+(5/3k-6)+2=0

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Solution for 2(1/3k-6)^2+(5/3k-6)+2=0 equation: 


k in (-oo:+oo)

2*((1/3)*k-6)^2+(5/3)*k-6+2 = 0

2*(1/3*k-6)^2+(5*k)/3-6+2 = 0

(2*3*(1/3*k-6)^2)/3+(5*k)/3+(-6*3)/3+(2*3)/3 = 0

2*3*(1/3*k-6)^2+5*k-6*3+2*3 = 0

2/3*k^2-19*k-18+6+216 = 0

2/3*k^2-19*k+6+198 = 0

2/3*k^2-19*k+204 = 0

2/3*k^2-19*k+204 = 0

2/3*k^2-19*k+204 = 0

DELTA = (-19)^2-(2/3*4*204)

DELTA = -183

DELTA < 0

1 = 0

1/3 = 0

1/3 = 0 // * 3

1 = 0

k belongs to the empty set

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